Question

If you lose control of your vehicle and collide with a fixed object, such as a tree, at 60 m.p.h., the force of impact is the same as driving your vehicle off a

Answer 1

You can compare the velocity of the car, 60 mph, with the velocity that a mass would acquire when falls from certain height.

First, convert 60 mph to m/s:

60 miles/h * 1.60 km/mile * 1000 m/km * 1h/3600s = 26.67 m/s

Second, calculate from what height a body in free fall reachs 26.67 m/s velocity when hits the floor.

free fall => Vf^2 = 2g*H => H = Vf^2 / (2g)

H = (26.67m/s)^2 / (2*9.8 m/s) = 36.2 m

If you consider that the height between the floors of a building is approximately 3.6 m, you get 36.2 m / 3.6 m/floor = 10 floors.

Then, you conclude that the force of impact is the same as driving you vehicle off a 10 story building.

Answer 2

The force of impact is the same as driving your vehicle off a 10.0 story structure.

Given the following data:

• Velocity = 60 mph.

Conversion:

• Velocity = 60 mph to m/s = 26.82 m/s.

How to calculate the height.

In this exercise, you're required to compare the force of impact with an equivalent height. Thus, we would use the following formula to calculate the height:

$H = \frac{V^2}{2g}$$H = \frac{V^2}{2g}$

Where:

• H is the height.

• V is the velocity.

• g is the acceleration due to gravity.

Substituting the parameters into the formula, we have;

H = \frac{26.82^2}{2(9.8)}

H = 36.70 meters.

Assuming a distance of 3.6 meters:

Height = \frac{36.70}{3.6}

Height = 10.0 meters.

Read more on forces here: brainly.com/question/1121817