Assume that maintenance costs per machine may be modeled by the linear relation
C = a + bx
where
x = machine hours
a, b are constants.
When x=8,000 hours, C=$1.50, therefore
a + 8000b = 1.5 (1)
When x=13,000 hours, C=$1.20, therefore
a + 13000b = 1.2 (2)
Subtract (2) from (1).
a + 8000b - (a + 13000b) = 1.5 - 1.2
-5000b = 0.3
b = -6 x 10⁻⁵
From (1), obtain
a = 1.5 - 8000*(-6 x 10⁻⁵) = 1.98
Therefore
C = 1.98 - 6x10⁻⁵ x
When machine hours is x=10,000, obtain
C = 1.98 - 6x10⁻⁵ * 10000
= 1.38
Answer: $1.38