Respuesta :
The answer is c. If you plug in 1 where there are x's. The numerator is 0 making the whole equation equal to 0.
Answer:
C. 1
Step-by-step explanation:
We have the rational expression, [tex]\frac{(x-1)}{(x-3)(x+1)}[/tex].
After equating the expression to 0, we get,
[tex]\frac{(x-1)}{(x-3)(x+1)}=0[/tex]
i.e. [tex](x-1)=0\times [(x-3)(x+1)][/tex]
i.e. [tex](x-1)=0[/tex]
i.e. x= 1
Thus, the value for which the rational expression is equal to 0 is x= 1.
Hence, option C is correct.