Question

how would you simplify -2+3i/-3-2i (im doing conjugates in math right now)

Answer 1

$\cfrac{-2+3i}{-3-2i}= \\ \\ \\ \cfrac{(-2+3i)(-3+2i)}{(-3-2i)(-3+2i)}= \\ \\ \\ \cfrac{6-4i-9i+6i^2}{9-4i^2}= \\ \\ \\ \cfrac{6-13i-6}{9+4}= \\ \\ \\ \cfrac{-13i}{13}=-1i$

hope this helps