Respuesta :
y = 3√(x-1).
Constraint: the radicand (x-1) ≥ 0 or x≥ 1
So the domain of this function is all Real for x ≥ 1
{x∈ R/x≥1}
Constraint: the radicand (x-1) ≥ 0 or x≥ 1
So the domain of this function is all Real for x ≥ 1
{x∈ R/x≥1}
Solution:
The given function is , [tex]y=3 \sqrt{x}-1[/tex]
Domain means, those values of y, for which x is defined.
As, [tex]\sqrt{x}[/tex] is defined for positive real number, that is from [0, ∞]→→Called closed interval.
So, Domain of function [tex]y=3 \sqrt{x}-1[/tex] is [0 ,∞]
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