Respuesta :

[tex]\bf \qquad \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\to &\$8000\\ r=rate\to 10.5\%\to \frac{10.5}{100}\to &0.105\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{monthly, thus twelve times} \end{array}\to &12\\ t=years\to &8 \end{cases} \\\\\\ A=8000\left(1+\frac{0.105}{12}\right)^{12\cdot 8}[/tex]
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