Question

A spinner is divided into 4 equal sections numbered 1 to 4. The theoretical probability of the spinner stopping on 3 is 25%. Which of the following is most likely the number of 3's spun in 10,000 spins?

Answer 1

To find how many times it will land on 3 in 10,00 spins you need to find 25% of 10,000 so 10,000 times .25 is the equation which is 2,500 so if I'm not mistaken the spinner should land on the third section 2,500 times in 10,000 spins theoretically speaking.

Answer 2

The expected value of an event is the mean or average of the event

The number of 3's spun in 10,000 spins is most likely 1200

The given parameters are:

$p =12\%$ -- the theoretical probability of the spinner stopping on 3

$n = 10000$ --- the number of spin

The expected value is then calculated as:

$E(x) = np$

So, we have:

$E(3) = 10000 * 12\%$

Evaluate the products

$E(3) = 1200$

Hence, the number of 3's spun in 10,000 spins is most likely 1200

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