Answer:
80 and 90 mph
Step-by-step explanation:
Given that A and B have a distance of 1029 miles between them. Two trains each start from A and B and move towards each other.
Let the speed of I train be s
Then speed of second train = s+10 (since 10 greater than speed of I train)
Relative speed = s+s+10 = 2s+10
In 5 hours they travelled together a distance of 1020-170 =850 miles
Distance travelled = 850 miles
Relative speed = 2s+10
Time taken = 5 hours
Since distance = time x speed
we have
5(2s+10) =850
2s+10 =170
s = 80
Speed of the trains are 80mph and 90 mph
Answer:
From points A and B, the distance between which is 1020 mi
The speed of one train was 10 mph greater than the speed of the other one
Let the Speed of first train is x
Speed of second train is x+ 10
Time = 5 hours
Distance = speed * time
Distance traveled by first train = x * 5= 5x
Distance traveled by second train = (x+10) * 5= 5x + 50
the trains had not met yet and were 170 mi apart.
the distance between A and B is 1020 mi, Distance traveled by two trains = 1020 - 170 = 850 miles
Distance traveled by first train + second train = 850
5x + 5x + 50 = 850
10x + 50 = 850
Subtract both sides by 50
10x = 800
x= 80
Speed of first train is 80 miles per hour
Speed of second train is 90 miles per hour
