Question

Triangle XYZ is located at X (−2, 1), Y (−4, −3), and Z (0, −2). The triangle is then transformed using the rule (x−1, y+3) to form the image X'Y'Z'. What are the new coordinates of X', Y', and Z'?

Answer 1

The given points are X (−2, 1), Y (−4, −3), and Z (0, −2)

By using the rule (x − 1, y + 3) the points then become:

X′ (− 2 − 1, 1 + 3), Y′ (− 4 − 1, − 3 + 3), and Z′ ( 0 −1, − 2 + 3)

X′ (− 3, 4), Y′ (− 5, 0), and Z′ (− 1, 1)

If the corresponding vertices of both triangles were connected with line segments then we should get exact congruent triangles with just x- and y-coordinates transformed or we can say that:

△XYZ=△X′Y′Z′

Answer: X′ (− 3, 4), Y′ (− 5, 0), and Z′ (− 1, 1)