Respuesta :

[tex]\bf n^{th}\textit{ term of a geometric sequence}\\\\ a_n=a_1\cdot r^{n-1}\qquad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ r=\textit{common ratio}\\ ----------\\ n=4\\ a_1=-2\\ r=-5 \end{cases}\implies a_4=-2(-5)^{4-1}[/tex]