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Question: The diagonals of rhombus FGHJ intersect at point K. If side GH is equal to x + 9 and side JH is equal to 5x - 2, find x.
       
Answer: Rhombus
I have all of the properties of the parallelogram PLUS
- 4 congruent sides
- diagonals bisect angles
- diagonals perpendicular
       
3x - 10 = 6x - 19
3x - 6x = -19 + 10
-3x = -9
x = -9/-3
x = 3

Answer:

x = 2.75

Step-by-step explanation:

5x - 2 = x + 9

5x = x + 11

4x = 11

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