For lines to be parallel to one another they must have the same slope. Our reference line has a slope of -2/3, so our parallel line is:
y=-2x/3+b, using the point (-2,-2) we can solve for "b", the y-intercept.
-2=-2(-2)/3+b
-2=4/3+b
-6/3-4/3=b
-10/3=b so our line is:
y=-2x/3-10/3 (or more neatly in my opinion :P)
y=(-2x-10)/3
It's the second one down from the top :)
