Question

Why is the answer (A)?

Answer 1

$\frac{1}{2}x^2+mx-5=0 \\ \\ x= \frac{-mб \sqrt{m^2-4* \frac{1}{2}*(-5) } }{2* \frac{1}{2} }= \frac{-mб \sqrt{m^2+10} }{1}=-mб \sqrt{m^2+10}$