Respuesta :
Any of the given 5 letters can be at the start of the code.
Total choices = 5
We want the code to start with A
Choices in favor = 1
Probability = favorable/total = 1/5 = 0.20
Total choices = 5
We want the code to start with A
Choices in favor = 1
Probability = favorable/total = 1/5 = 0.20
Answer:
(C)0.20
Step-by-step explanation:
We are given that we have to make five-letter codes that use the letters A, F, E, R, and M without repeating any letter.
Thus, total number of letters=5
Now, the probability that a randomly chosen code starts with A is given as:
[tex]P=\frac{Favourable outcomes}{Total number of outcomes}[/tex]
[tex]P=\frac{1}{5}[/tex]
[tex]P=0.20[/tex]
Therefore, the the probability that a randomly chosen code starts with A is 0.20.
Hence, option C is correct.