Answer:
b
Step-by-step explanation:
we have
[tex]\sqrt{b}*\sqrt{b}[/tex]
Rewrite the expression
[tex]\sqrt{b}*\sqrt{b}=(b^{\frac{1}{2}})*(b^{\frac{1}{2}})[/tex]
we know that
When multiplying two powers that have the same base, you can add the exponents
so
[tex](b^{\frac{1}{2}})*(b^{\frac{1}{2}})=b^{(\frac{1}{2}+\frac{1}{2})}=b^{1}=b[/tex]
