Respuesta :
Attraction (right?), so the + charge will try to go to the - charge. Force on + charge will be directed towards left. The magintude is Coulomb's law:
F = k * Q1*Q2/d^2, K = 9*10^9, Q1 = -4*10^(-6), Q2 = 6*10^(-6), and d = 0.45
-9*4*6*10^(-3)/0.45^2 = -1.0633 N, but check it (sign means attractive).
Some teachers prefer to say that magnitude is always positive, like in math, so 1.0633 N but then say attractive and directed to the left of the + charge, to make sure no one can complain you miss anything! Ask your teacher
F = k * Q1*Q2/d^2, K = 9*10^9, Q1 = -4*10^(-6), Q2 = 6*10^(-6), and d = 0.45
-9*4*6*10^(-3)/0.45^2 = -1.0633 N, but check it (sign means attractive).
Some teachers prefer to say that magnitude is always positive, like in math, so 1.0633 N but then say attractive and directed to the left of the + charge, to make sure no one can complain you miss anything! Ask your teacher
Because of negative side the direction of Electrostatic force will be right to left that means to the left
Magnitude of Electrostatic force will be = 1.0667 N
What is electrostatic force ?
The electrostatic force is an attractive and repulsive force between charged particles . The electric force between stationary charged bodies conventionally known as electrostatic force .
q1 = –4.0 µC
q2 = +6.0 µC
r = 0.45 m
k= 9 * 10 ^ 9
(E) Electrostatic force = k *q1* q2 / r^2
E = (9 * 10 ^ 9) *( –4.0) * ( +6.0) / (0.45)^2
E = - 1066.67 * 10 ^ (-3)
Electrostatic force = - 1.0667 N
Because of negative side the direction of Electrostatic force will be right to left that means to the left
magnitude of Electrostatic force will be = 1.0667 N
learn more about Electrostatic force
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