The window shown is the shape of a semicircle with a radius of 6 feet. The distance from F to E is 3 feet and the measure of = 45°. Find the area of the glass in region BCIH, rounded to the nearest square foot. ft2
We have to find 2 areas and to subtract A2 from A1: A1 = ( r² · π · 45° ) / 360° = ( 6² · 3.14 · 45° ) / 360° = 14.13 ft² A2 = ( 3² · π · 45° ) / 360° = 3.53 ft² A ( BCIH ) = 14.13 - 3.53 = 10.6 ft² ≈ 11 ft² Answer: The area of the glass in the region BCIH is 11 ft² ( rounded to the nearest square foot ).
