Question

find the sum to the equation of:

Answer 1

$\frac{a}{a^{2} - 4a + 4} + \frac{7}{a^{2} + 2a - 8}$ = $\frac{a(a^{2} + 2a - 8)}{(a^{2} - 4a + 4)(a^{2} + 2a - 8)} + \frac{7(a^{2} - 4a + 4)}{(a^{2} - 4a + 4)(a^{2} + 2a - 8)}$ = $\frac{a^{3} + 2a^{2} - 8a}{a^{4} - 2a^{3} - 12a^{2} + 40a - 32} + \frac{7a^{2} - 28a + 28}{a^{4} - 2a^{3} - 12a^{2} + 40a - 32}$ = $\frac{a^{3} + 9a^{2} - 36a + 28}{a^{4} - 2a^{3} - 12a^{2} + 40a - 32}$