Question

What is the equation of the line whose slope is 3 that passes through the point (-1, 5).

y = 3x + 5
y = 3x - 1
y = 3x + 8
y = 3x + 2

Answer 1

we knownthe equation of a line is y = mx + b. where m is slope and b is y intercept.

the point slope equation of a line is y - y1 = m (x - x1)

plug in x1 and y1 and m
y- (5) = (3)(x - (-1))
y - 5 = 3x + 3
y = 3x + 8