Respuesta :

Al³⁺ + 3e⁻ →  Al      the reduction half-reaction

Answer: The half reaction for reduction reaction is [tex]Al^{3+}(aq.)+3e^-\rightarrow Al(s)[/tex]

Explanation:

Reduction reaction is defined as the reaction in which a substance gains electrons and the oxidation state of the substance is reduced.

Oxidation reaction is defined as the reaction in which a substance looses electrons and the oxidation state of the substance is increased.

For the given redox reaction:

[tex]Ca(s)+Al(NO_3)_3(aq.)\rightarrow Al(s)+Ca(NO_3)_2(aq.)[/tex]

The half cell reactions for the above redox equation is:

Oxidation: [tex]Ca(s)\rightarrow Ca^{2+}(aq.)+2e^-[/tex]

Reduction: [tex]Al^{3+}(aq.)+3e^-\rightarrow Al(s)[/tex]

Hence, the half reaction for reduction reaction is [tex]Al^{3+}(aq.)+3e^-\rightarrow Al(s)[/tex]

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