After the fraction x plus 2 all over 3 minus the fraction x plus 1 all over 2x have been combined using the least common denominator of 6x, what is the numerator?

SOS

 2x2 + x − 3 
2x2 + x − 1
 
−2x2 + x + 6
 
−x2 + 2x + 6

Respuesta :

I'm pretty sure the answer is 2x2 + x -3

Answer:

a. [tex]2x^{2} +x-3[/tex]

Step-by-step explanation:

[tex]\frac{x+2}{3} -\frac{x+1}{2x}\\\\=(\frac{x+2}{3} *\frac{2x}{2x} )-(\frac{x+1}{2x} *\frac{3}{3} )\\\\=\frac{2x^{2}+4x }{6x} -\frac{3x+3}{6x} \\\\=\frac{2x^{2}+4x-3x-3 }{6x} \\\\=\frac{2x^{2} +x-3}{6x}[/tex]

Therefor the numerator is:

[tex]2x^{2} +x-3[/tex]

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