A.) Given that the
official U.S. population was 248.7 million in 1990 and 308.7 million in
2010.
To find the average change in population per year from 1990
through 2010, let the year be represented by x, and the population in that year be represented by f(x).
Recall that the average rate of change of a function over a given interval, (a, b) is given by
[tex] \frac{f(b)-f(a)}{b-a} [/tex]
Thus, the average change in population per year from 1990
through 2010 is given by
[tex] \frac{308.7-248.7}{2010-1990} = \frac{60}{20} =3[/tex]
Therefore, the average change in population per year from 1990
through 2010 is 3 million.
B.) From part a, we obtained that the population grows at a rate of 3 million per year.
Given that [tex]p_0=281.4[/tex] is the initial value of the population in 2000 and [tex]p_n[/tex] is the population, n, years after 2000.
Thus, a recursive formula for the sequence [tex]p_n[/tex] is given by
[tex]p_n=p_{n-1}+3, \ p_0=281.4[/tex]
C.) Recall that the explicit formula for an arithmetic sequence with firstterm, a, and common difference, d is given by
[tex]p_n=a+(n-1)d[/tex]
Given that a = [tex]p_0[/tex] = 281.4 and, d = 3, thus an explicit formula for the arithmetic sequence [tex]p_n[/tex] is given by
[tex]p_n=281.4+(n-1)3=281.4+3n-3=278.4+3n \\ \\ \bold{p_n=278.4+3n}[/tex]
D.) Using the formula obtained in part C, notice that 2010 is 10 years after 2000, 2015 is 15 years and 2020 is 20 years after 2000.
For, 2010:
[tex]p_n=278.4+3(10)=278.4+30=308.4[/tex]
For 2015:
[tex]p_n=278.4+3(15)=278.4+45=323.4[/tex]
For 2020:
[tex]p_n=278.4+3(20)=278.4+60=338.4[/tex]