The balanced chemical equation for the reaction is
From the question given above, we were told that:
Aqueous hydrochloric acid reacts with solid manganese (iv) oxide to form aqueous manganese(ii) chloride, liquid water and chlorine gas.
The equation for the reaction can be written as follow:
Hydrochloric acid => HCl
Manganese (iv) oxide => MnO₂
Manganese (ii) chloride => MnCl₂
Water => H₂O
Chlorine gas => Cl₂
Hydrochloric acid + Manganese (iv) oxide —> Manganese (ii) chloride + Water + Chlorine gas
The above equation can be balance as follow:
HCl + MnO₂ → MnCl₂ + H₂O + Cl₂
There are 2 atoms of O on the left side and 1 atom on the right side. It can be balance by writing 2 before H₂O as shown below:
HCl + MnO₂ → MnCl₂ + 2H₂O + Cl₂
There are 4 atoms of H on the right side and 1 atom on the left side. It can be balance by writing 4 before HCl as shown below:
4HCl(aq) + MnO₂(s) → MnCl₂(aq) + 2H₂O(l) + Cl₂(g)
Now, the equation is balanced.
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