According to the americans with disabilities act, a ramp can rise no more than 1 ft for every 12 ft of horizontal distance. what is the maximum angle that a ramp can form with the ground?

Respuesta :

4.76 degrees; tan(-) =1/12 –> tan (inverse) 1/12 = 4.76 degrees

I used (-) as theta; you solve this using your calculator

Answer:

The maximum angle that a ramp can form with the ground is 4.76°.

Step-by-step explanation:

Assuming the ramp as a right-angled  triangle, and letting the horizontal distance being the  leg adjacent and the vertical distance the leg opposite, then the tangent to the ramp angle will be:

[tex] tg(a) = adj/opp [/tex]

The angle a is solving by the inverse of the leg's rate:

[tex] a = tg^{-1}(adj/opp) [/tex]

[tex] a = tg^{-1}(1 ft / 12 ft) = tg^{-1}(0.83) = 4.72\°[/tex]

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