Respuesta :
I think yes i do.. cuz using yr information i get the distance i travelled before stopping become 49.62144 m, using the formula distance travelled/time taken= (final velocity+initial velocity)/2.
I am not sure tht its the right answer but using my calculation I got this so hope there! :)
I am not sure tht its the right answer but using my calculation I got this so hope there! :)
Answer:
You get a ticket you speed is around 68 mi/hr
Explanation:
[tex]V_{f} =V_{i} + a*t[/tex]
[tex]V_{i} = 73 \frac{mi}{hr} *\frac{1 hr}{3600 s} * \frac{1609,34m}{1 mi} = 32.6339 \frac{m}{s}[/tex], [tex]a=-2 \frac{ft}{s^{2} } * \frac{0.3048m}{1 ft} =-0.6096 \frac{m}{s^{2} }[/tex]
[tex]V_{f} =32.6339\frac{m}{s} -0.6096 \frac{m}{s^{2} } *3 s[/tex]
[tex]V_{f} = 30.8051\frac{m}{s} *\frac{3600 s}{hr} * \frac{1 mi}{1609.34m} = 68.909 \frac{mi}{hr}[/tex]
You still in trouble because the speed is still above the allowed