Respuesta :
Hey there!
These are technically expressed as fraction. When you divide a fraction by another, you can replace the second fraction with its reciprocal and you can now multiply the fractions together instead.
[tex]\frac{x^2-x-12}{2x^2} / \frac{x^2+x-6}{2x^3}[/tex]
[tex]\frac{x^2-x-12}{2x^2} * \frac{2x^3}{x^2+x-6}[/tex]
Now, just multiply across the top and the bottom. You can first cancel out any terms that are repeated or similar.
[tex]\frac{12}{2x^2} * \frac{2x^3}{-6}[/tex]
[tex]\frac{2}{x} * \frac{1}{-1}[/tex]
[tex]\frac{2}{-x}[/tex]
Your answer will be [tex]\frac{2}{-x}[/tex].
Hope this helped you out! :-)
These are technically expressed as fraction. When you divide a fraction by another, you can replace the second fraction with its reciprocal and you can now multiply the fractions together instead.
[tex]\frac{x^2-x-12}{2x^2} / \frac{x^2+x-6}{2x^3}[/tex]
[tex]\frac{x^2-x-12}{2x^2} * \frac{2x^3}{x^2+x-6}[/tex]
Now, just multiply across the top and the bottom. You can first cancel out any terms that are repeated or similar.
[tex]\frac{12}{2x^2} * \frac{2x^3}{-6}[/tex]
[tex]\frac{2}{x} * \frac{1}{-1}[/tex]
[tex]\frac{2}{-x}[/tex]
Your answer will be [tex]\frac{2}{-x}[/tex].
Hope this helped you out! :-)
I strongly urge you to use parentheses here, to remove any ambiguity regarding which quantity is being divided by which quantity. I'm assuming that you meant
(x^2−x−12)/(2x^2)÷(x^2+x−6)/2x^3. If that is correct, great. If not, fix it! Once correct, you can perform the divisions from left to right, beginning with (x^2-x-12)/2x^2.
(x^2−x−12)/(2x^2)÷(x^2+x−6)/2x^3. If that is correct, great. If not, fix it! Once correct, you can perform the divisions from left to right, beginning with (x^2-x-12)/2x^2.