Respuesta :

[tex]\bf \qquad \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\to &\$2410\\ r=rate\to 12\%\to \frac{12}{100}\to &0.12\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{monthly, thus} \end{array}\to &12\\ t=years\to &3 \end{cases} \\\\\\ A=2410\left(1+\frac{0.12}{12}\right)^{12\cdot 3}[/tex]
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