Question

the sum of three numbers is 131. The second of three numbers is seven more than twice the first. The third number is 12 less than first . What equation can be used to solve the problem

Answer 1

No. 1 = x
No. 2 = 2x+7
No. 3 = x-12

Answer:

x+(2x+7)+(x-12) = 131

From there you solve to get the numbers:

34, 75 and 22