A = length x width
15,000 = (w + 30) x w
15,000 = [tex] w^{2} [/tex] + 30w
0 = [tex] w^{2} [/tex] + 30w - 15,000
Use quadratic formula to find that w= -15 + or - 5[tex] \sqrt{609} [/tex]. Because distance cannot be negative, the width is -15 + 5[tex] \sqrt{609} [/tex]meters or approximately 108.39 meters. This means that the length is approximately 138.39 meters.
