Respuesta :
Answer:
Option D.
Step-by-step explanation:
The given expression is :[tex]\frac{x}{x^{2}-2x-15 } -\frac{4}{x^{2} +2x-35}[/tex]
Factoring the denominators we have:
[tex]\frac{x}{(x-5)(x+3)} -\frac{4}{(x+7)(x-5)}[/tex]
Making denominators same and simplifying the fractions we have:
[tex]\frac{x^{2}+7x-4x-12 }{(x-5)(x+3)(x+7)} =\frac{x^{2}+3x-12 }{(x+3)(x-5)(x+7)}[/tex]
Option D is the right anser.
