A ball is thrown vertically upward. After t seconds, its height h (in feet) is given by the function =ht−64t16t2. What is the maximum height that the ball will reach?

Respuesta :

This is the concept of applications of polynomial equations. Given that the height of the ball is modeled by the function:
h(t)=16t^2-64t
the maximum height will be calculated as follows;
h(t)=16t(t-4)
therefore:
t=0 or t=4
h(4)=-64(4)+16(4^2)
=0

Answer:

2 seconds

Step-by-step explanation:

i just took a quiz and this was the answer.

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