Question

Find the missing term in the equation. 4x2 − 8x + 8 − x2 + 2x − 4 − 3x2 +_ = 4

Answer 1

I am assuming you in your question mean 4x^2-8x+8-x^2+2x-4-3x^2+_=4
4x^2-x^2-3x^2=0 so you get
-8x+8+2x-4+_=4
-6x+4+_=4
so _=6x

Answer 2

Answer:

+6x

Step-by-step explanation:

Given is an equation with a missing term as follows:

$4x^2 -8x + 8 -x^2 + 2x -4 - 3x^2 +_ = 4$

Simplify by grouping the like terms as follows:

$(4x^2- 3x^2- x^2) +(-8x   + 2x )+( 8-4)  +_ = 4\\-6x+4+_ =4\\-6x+_=0$

Thus missing term must be

+6x