Respuesta :
hello :
this arithmetic sequence the first term is : A1 = 3(1)+2=5
and common difference is r = 3
the sum of the first 50 terms is : S50 = 50/2(A1 + A50)
A50 = 3(50)+2 = 152
S50 = 50/2(5 + 152)= 3925
this arithmetic sequence the first term is : A1 = 3(1)+2=5
and common difference is r = 3
the sum of the first 50 terms is : S50 = 50/2(A1 + A50)
A50 = 3(50)+2 = 152
S50 = 50/2(5 + 152)= 3925
Answer with Step-by-step explanation:
The sum of first n terms of an arithmetic progression is given by:
[tex]S(n)=\dfrac{n}{2}\times (A1+An)[/tex]
We are given n=50 and we have to find S(50)
[tex]S(50)=\dfrac{50}{2}\times (A1+A50)[/tex]
A1=3×1+2=5
A50=3×50+2=152
[tex]S(50)=\dfrac{50}{2}\times (5+152)[/tex]
S(50)=25×157
=3,925
Hence, sum of the first 50 terms in An = 3n + 2 is:
3,925