Question

Consider the nuclear equation below.

What is the nuclide symbol of X?

A) 230/90Th
B) 229/89Ac
C) 228/90Th
D) 228/88Ra

Answer 1

Answer;

C) 228/90Th

Explanation;

-The above nuclear equation shows a beta radiation. The nuclide X undergoes beta radiation to form 228/89 Ac.

- When an unstable nuclide undergoes beta radiation the mass number remains the same while the atomic number is increased by one.

-Therefore, we can get the mass number and the atomic number of nuclide X, The mass number would be the same as 228 (its not affected by beta radiation) and the atomic number would be 89 (88+1).

Answer 2

The nuclide symbol of the given nuclear equation is 228/88Ra. Details about nuclear equations can be found below.

What is a nuclear equation?

A nuclear equation is one which involves the emission of radiation by the nucleus of an atom.

According to this question, a nuclide X undergoes a beta radiation to form 228/89Ac. A beta particle possesses mass number and atomic number of 0 and -1 respectively.

This means that when an atom undergoes beta radiation, the atomic number is increased by 1 but the mass number remains unchanged.

Therefore, the nuclide symbol of the given nuclear equation is 228/88Ra.

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