Question

Find the difference. (4x 2 - 6x + 8) - (3x 2 - 6x + 2)

Answer 1

$(4x^2 - 6x + 8) - (3x^2 - 6x + 2)\\~\\=4x^2 - 6x + 8-3x^2 + 6x - 2\\~\\~=(4x^2-3x^2)+(- 6x+6x)+(8-2)\\~\\=x^2+0+6\\~\\=x^2+6$


The idea is to combine like terms and simplify

I hope that helps!