Question

bubble wrap sells in sheets, and each sheet has 1 million individual spherical bubbles, each with a diameter of 0.01 m. what is the total volume of air contained in the bubbles of two sheets of bubble wrap? round to the nearest tenth.

Answer 1

volume of sphere = V=(4/3) x PI x r^3

V = (4/3) x 3.14 x 0.005^3 = 5.2x10^-7 x 1 million = 0.52 cubic meters per sheet

0.52 x 2 = 1.0 cubic meters

Answer 2

Answer:

The total volume is 1.0 m³

Step-by-step explanation:

We know that, the volume of a sphere is,

$V=\frac{4}{3}\pi (r)^3$

Where, r is the radius of the sphere,

For a bubble,

r = 0.01/2 = 0.005 m,

Thus, the volume of a bubble,

$V=\frac{4}{3}\pi (0.005)^3$

$=\frac{4}{3}\times \frac{22}{7}\times 0.000000125$

$=5.2380952381\times 10^{-7}\text{ cube m}$

Since, a sheet of paper has 1 million individual spherical bubbles,

The bubble contained by 2 papers = 2 million,

And, the volume of 2 million bubbles = 2,000,000 × Volume of a bubble

= 1.04761904762 m³

≈ 1.0 m³

Hence, the total volume of air contained in the bubbles of two sheets of bubble wrap is 1.0 m³