A newspaper carrier has $7.30 in change. He has four more quarters than dimes but four times as many nickels as quarters. How many coins of each type does he have?
Let d be dimes. Then quarters would be d+4; and nickels would be 4(d+4). Then: .05(4d+16)+.1d+.25(d+4)=7.3 .2d+.8+.1d+.25d+1=7.3 .55d=5.5 d=10 Plug d=10 to get quarters and nickels. ☺☺☺☺
