Answer:
[tex]3y-2x>-18[/tex]
Step-by-step explanation:
We are given with a linear equation [tex]3y-2x> -18[/tex] . We have to draw this inequality.
In order to draw this inequality , we have to first draw the graph of
[tex]3y-2x= -18[/tex]
Let us do it , by converting the equation into intercept form, and find the x and y intercepts.
Divide both side, each term by -18 , we get
[tex]\frac{3y}{-18}-\frac{2x}{-18}= \frac{-18}{-18}[/tex]
[tex]\frac{y}{-6}-\frac{x}{-9}= 1[/tex]
[tex]\frac{y}{-6}+\frac{x}{9}= 1[/tex]
[tex]\frac{x}{9}+\frac{y}{-6}= 1[/tex]
Hence our x intercept = 9
y intercept = -6
Hence the line passes through the coordinates (9,0) and (0,-6). We now plot them on graph and draw our line.
Now we have to check which region to shade.
Our inequality is given as [tex]3y-2x>-18[/tex]
Let us see whether (0,0) satisfies this inequality. For that we need to substitute them in our equation.
[tex]3(0)-2(0)>-18[/tex]
[tex]0-0>-18[/tex]
[tex]0>-18[/tex]
Which is true .
Hence , we shade the region which is containing (0,0) . Also our line need to be broken as it is containing > sign in it.
