If there is no air resistance and the body,
in this case the sky diver simply falls from the helicopter then, the motion
can be described as a free-falling body. The equation that would allow us to
determine the speed of the body at any time, t is,
v(t) = vo + gt
where v(t) is the unknown velocity, vo is the
initial velocity which is equal to zero and g is the acceleration due to
gravity which is equal to 9.8 m/s2.
Substituting the known values,
v(t)
= 0 + (9.8 m/s2)(12s)
v(t)
= 117.6 m/s
Hence, the speed of the sky diver at the end
of 12 second is approximately 117.6 m/s.
