Respuesta :

We want to solve
[tex] \sqrt{x^2+49}=x+5 [/tex]

Square each side.
x^2 + 49 = (x + 5)^2
x^2 + 49 = x^2 + 10x + 25
49 = 10x + 25 
24 = 10x
x = 24/10 = 12/5

Test the answer.
[tex] \sqrt{( \frac{12}{5})^2+49} = \frac{37}{5} [/tex]
[tex] \frac{12}{5} +5= \frac{37}{5} [/tex]
The solutionis correct.

Answer: 12/5

The value of x is 12/5.

Given

Equation; [tex]\rm \sqrt{x^2+49} =x+5[/tex]

How do find the solution to the equation?

To find the solution of the equation first square both sides then simplify the equation then simplify the value of x.

Then,

The value of x is;

[tex]\rm \sqrt{x^2+49} =x+5[/tex]

Squaring on both sides

[tex]\rm x^2+49=(x+5)^2\\\\x^2+49=x^2+10x+25\\\\x^2+49-x^2-10x-25=0\\\\25-10x=0\\\\10x=24\\\\x=\dfrac{24}{10}\\\\x= \dfrac{12}{5}\\\\[/tex]

Hence, the value of x is 12/5.

To know more about Equation click the link given below.

https://brainly.com/question/4192440

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