First the left side of an equation:"six added to twice the sum of a number and four": ( x - a number )
6 + 2 ( x + 4 )Then the right side:"one half of a difference of three and a number":1/2 ( 3 - x )And the solution:A ) 6 + 2 ( x + 4 ) = 1/2 ( 3 - x )