Answer:
(C)[tex]v=\frac{4}{3d-12}[/tex]
Step-by-step explanation:
It is given that [tex]l=\frac{d-2}{3d-9}[/tex], [tex]w=\frac{4}{d-4}[/tex] and [tex]h=\frac{2d-6}{2d-4}[/tex]
Substituting these values in [tex]v=lwh[/tex], we have
[tex]v=(\frac{d-2}{3d-9})(\frac{4}{d-4})(\frac{2d-6}{2d-4})[/tex]
[tex]v=(\frac{d-2}{3(d-3)})(\frac{4}{d-4})(\frac{2(d-3)}{2(d-2)})[/tex]
[tex]v=\frac{4}{3(d-4)}[/tex]
[tex]v=\frac{4}{3d-12}[/tex]
Therefore, option C is correct.
Answer:Option C is correct.
4/3d-12
Step-by-step explanation:
Answer on Edgen