If the length of one base of a trapezoid is 5, the length of the other base is 2x + 7, and the length of the midsegment is 6x – 24, what is the value of x? show equations and all work that leads to your answer.
The length of the midsegment of a trapizoid is equal to the average of the 2 bases, therefore... [tex] \frac{(2x+7)+5}{2} =6x+24[/tex] And From that point on you use algebra to solve the problem. [tex] \frac{2x+12}{2} =6x+24
[/tex] [tex]x+6=6x+24[/tex][tex]6=5x+24[/tex][tex]6=5x+24[/tex][tex]-18=5x[/tex][tex]x= \frac{-18}{5} [/tex] I Hope this answer helps
