The formula v=√64h can be used to find the velocity v in feet per second of an object that has fallen h feet. When the velocity of an object reaches 38 feet per second, how far has it fallen?


A) 30.59 feet
B) 49.32 feet
C) 306.93 feet
D) 22.56 feet

Respuesta :

v = sqrt 64h

38 = sqrt 64h
38^2 = 64h
1444 = 64h
1444/64 = h
22.56 = h <===

Answer:

The velocity of an object reaches 38 feet per second,then the height it has fallen is:

                      D) 22.56 feet

Step-by-step explanation:

The formula that is used to relate the velocity and height of of an object  by:

[tex]v=\sqrt{64h}[/tex]

where v is the velocity of the object and h is the height of the object how far it has fallen.

Now, we are asked to find the value of h when v=38

Hence, we get:

[tex]38=\sqrt{64h}[/tex]

on squaring both side of the equation we get:

[tex](38)^2=64h\\\\i.e.\\\\h=\dfrac{(38)^2}{64}\\\\i.e.\\\\h=\dfrac{1444}{64}\\\\i.e.\\\\h=22.5625[/tex]

Hence, the correct answer is:  Option: D

ACCESS MORE
EDU ACCESS