Question

a rock climber averages 12 and 3/5 feet per minute. Write and solve an equation to find how many feet x the rock climber climbs in 30 minutes.an equation is ___= 12 and 3/5The rock climber climbs ___ feet in 30 minutes

Answer 1

(12 3/5) / 1 = x / 30 ....(12 3/5 ft to 1 min = x ft to 30 min)
cross multiply
(1)(x) = (12 3/5)(30)
x = 63/5 * 30
x = 1890/5
x = 378 ft <==

Answer 2

Answer

An equation is $\frac{x}{30} =12\frac{3}{5}$

The rock climber climbs 378 feet in 30 minutes

Explanation

To solve this, we are going to use the velocity equation:

$velocity=\frac{distance}{time}$

We know from our problem that the climber averages 12 and 3/5 feet per minute, so their velocity is 12 and 3/5 feet per minute; in other words: $velocity=12\frac{3}{5}$. The problem is asking of for the distance $x$ that the rock climber climbs in 30 minutes, so $distance=x$ and $time=30$. Let's replace the values in our velocity equation:

$velocity=\frac{distance}{time}$

$12\frac{3}{5}=\frac{x}{30}$

Which is the same as $\frac{x}{30}=12\frac{3}{5}$

Now that we have our equation, we can solve for $x$ to find how much distance he climbs in 30 minutes:

$\frac{x}{30}=12\frac{3}{5}$

$x=12\frac{3}{5} *30$

$x=12.6*30$

$x=378$

He climbs 378 feet in 30 minutes.