Question

Which is a quadratic function having a leading coefficient of 3 and a constant term of –12? f(x) = –12x2 + 3x + 1 f(x) = 3x2 + 11x – 12 f(x) = 12x2 + 3x + 3 f(x) = 3x – 12

Answer 1

I think it is f(x)= 3x2+11x-12

Answer 2

The equation has a leading coefficient of 3 and a constant term of –12 is $\rm f(x) = 3x^2 + 11x - 12$.

We have to determine

Which is a quadratic function having a leading coefficient of 3 and a constant term of –12?

Quadratic Equation;

A quadratic equation is an equation that can be written in the form of;

ax²+bx+c= 0

Where a is the leading coefficient, and c is the constant.

What is the leading coefficient?

The leading coefficient of an equation is a coefficient of the term having the highest power in the equation.

It is given that the leading coefficient of the equation is 3.

Then,

The value of a is 3.

$\rm f(x)= 3x^2+bx+c$

And the value of the constant term is c which is -12.

$\rm f(x)= 3x^2+bx-12$

Therefore;

The equation has a leading coefficient of 3 and a constant term of –12 is $\rm f(x) = 3x^2 + 11x - 12$.

To know more about the Leading coefficient click the link given below.

https://brainly.com/question/2416002