Question

ƒ(x) = –x2 – 4 for x = –3.

Answer 1

I'm assuming it looks like this:

$f(x) = -x^2 - 4$

So we start by plugging -3 for x

$f(-3) = -(-3)^2 - 4$

Which becomes:

$f(-3) = 3^2 - 4$

Now simplify

$f(-3) = 9 - 4$

$f(-3) = 5$