Respuesta :
The probability tests to detect a liver disorder:
P (presence)= 0.98 (true) 0.02 (false)
P (absence)= 0.97 (true) 0.03 (false)
P(have disorder from the population)=0.035
P(do not have disorder from the population)= 0.965
To test positive:
P[have disorder and true from P(presence)] + P[do not have disorder and false from P(absence)]
=0.035*0.98+0.965*0.03= 0.06325
The answer is 0.06325
P (presence)= 0.98 (true) 0.02 (false)
P (absence)= 0.97 (true) 0.03 (false)
P(have disorder from the population)=0.035
P(do not have disorder from the population)= 0.965
To test positive:
P[have disorder and true from P(presence)] + P[do not have disorder and false from P(absence)]
=0.035*0.98+0.965*0.03= 0.06325
The answer is 0.06325
Answer:
Yes, the answer is 0.06
Step-by-step explanation:
I just did it on Edmentum.