Leanne deposited $1,500 into a savings account for which simple interest is calculated quarterly. If her $1,500 grew to $1,509 after 3 months, what is the yearly interest rate on Leanne's account? A. 6% B. 2.4% C. 0.24% D. 0.6% Mathematics

Respuesta :

The answer would be B 2.4%. 

After doing 9/375 = .024, you just move the decimal 2 places over to find the percentage.

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Answer:

Option B is correct

2.4%

Step-by-step explanation:

Using the formula:

[tex]A = P+Prt[/tex]

⇒[tex]A = P(1+rt)[/tex]           .....[1]

where,

P is the principal amount

A is the Amount after t years

r is the rate expressed in decimal

As per the statement:

Leanne deposited $1,500 into a savings account for which simple interest is calculated quarterly.

⇒[tex]P = \$1500[/tex]

It is also given that:  If her $1,500 grew to $1,509 after 3 months

⇒[tex]A = \$1509[/tex] and t = [tex]\frac{3}{12} = \frac{1}{4} =0.25[/tex] years

Substitute these given values in [1] we have;

[tex]1509 = 1500(1+0.25r)[/tex]

Divide both sides by 1500 we have;

[tex]1.006 = 1+0.25r[/tex]

Subtract 1 from both sides we have;

[tex]0.006 = 0.25r[/tex]

Divide both sides by 0.25 we have;

[tex]0.024 = r[/tex]

or

r = 0.024 or 2.4%

Therefore,  the yearly interest rate on Leanne's account is, 2.4%

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