Respuesta :
First find the slope of the line.
m=slope=(y2-y1)/(x2-x1), in this case:
m=(-1-7)/(9--3)
m=-8/12
m=-2/3
You did not specify which form of the line you wanted.
Slope-intercept form is y=mx+b
y=-2x/3+b, using pint (9,-1) we can solve for b, the y-intercept...
-1=-2(9)/3+b
-1=-6+b
5=b then we have:
y=-2x/3+5 or more neatly
y=(-2x+15)/3
Point-slope form of a line is:
y-y1=m(x-x1), again using (9,-1) as the point and m=-2/3 you get:
y+1=(-2/3)(x-9)
Standard form of a line is ax+by+c:
We can rearrange y=(-2x+15)/3 to standard form
y=(-2x+15)/3 multiply both sides by 3
3y=-2x+15 add 2x to both sides
2x+3y=15
m=slope=(y2-y1)/(x2-x1), in this case:
m=(-1-7)/(9--3)
m=-8/12
m=-2/3
You did not specify which form of the line you wanted.
Slope-intercept form is y=mx+b
y=-2x/3+b, using pint (9,-1) we can solve for b, the y-intercept...
-1=-2(9)/3+b
-1=-6+b
5=b then we have:
y=-2x/3+5 or more neatly
y=(-2x+15)/3
Point-slope form of a line is:
y-y1=m(x-x1), again using (9,-1) as the point and m=-2/3 you get:
y+1=(-2/3)(x-9)
Standard form of a line is ax+by+c:
We can rearrange y=(-2x+15)/3 to standard form
y=(-2x+15)/3 multiply both sides by 3
3y=-2x+15 add 2x to both sides
2x+3y=15
The equation of the line that passes through the points [tex]\left({ - 3,7}\right)[/tex] and [tex]\left({9, - 1}\right)[/tex] is [tex]\boxed{2x + 3y = 15}[/tex] .
Further explanation:
The linear equation with slope m and intercept c is given as follows.
[tex]\boxed{y = mx + c}[/tex]
The formula for slope of line with points [tex]\left({{x_1},{y_1}}\right)[/tex] and [tex]\left({{x_2},{y_2}}\right)[/tex] can be expressed as,
[tex]\boxed{m=\frac{{{y_2}-{y_1}}}{{{x_2}-{x_1}}}}[/tex]
Given:
The passes through the points are [tex]\left({ - 3,7}\right)[/tex] and [tex]\left({9, - 1}\right)[/tex] .
Explanation:
The line passes the points that are [tex]\left({ - 3,7}\right)[/tex] and [tex]\left({9, - 1}\right)[/tex].
The slope of the line can be obtained as follows.
[tex]\begin{aligned}m&=\frac{{ - 1 - 7}}{{9-\left({ - 3}\right)}}\\&=\frac{{ - 8}}{{12}}\\&=-\frac{2}{3}\\\end{aligned}[/tex]
The slope of the line is m = [tex]- \frac{2}{3}[/tex].
The line passes through the point [tex]\left({9, - 1}\right)[/tex].
Substitute 9 for x, [tex]- \frac{2}{3}[/tex] for m and -1 for y in equation y = mx + c to obtain the value of c.
[tex]\begin{aligned}-1&=\frac{{-2}}{3}\left(9\right)+c\\-1&=-2\left(3\right)+c\\-1&=-6+c\\-1+6&=c\\5&=c\\\end{aligned}[/tex]
Hence, the equation of the line that passes through the points [tex]\left({ - 3,7}\right)[/tex] and [tex]\left({9, - 1}\right)[/tex] is [tex]\boxed{2x + 3y = 15}[/tex].
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Answer details:
Grade: High School
Subject: Mathematics
Chapter: Linear equation
Keywords: numbers, slope, slope intercept, inequality, equation, linear inequality, shaded region, y-intercept, graph, representation, origin.